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本帖最后由 Gautau 于 2011-7-13 01:33 编辑
由于短期内不会开贴讨论 SRPP,故先来一些资料供大家參考。
Diyaudio坛內的讨论:
You may be confusing output impedance with optimum load. They are not the same thing. To add confusion, different people seem to give different formulas. I have been doing an analysis of the SRPP which one day I might publish. My results are:
output impedance Zout is
(Ra1+(mu+1)Rk1 + Rk2)Ra2/(Ra1+(mu+1)Rk1+Ra2+(mu+1)Rk2)
where Ra is anode impedance, Rk is cathode resistor (which may be zero if bypassed), suffix 1 refers to lower valve and 2 to upper valve. For identical valves and lower cathode resistor bypassed (and smallish Rk), this simplifies to (Ra^2)/(2Ra+(mu+1)Rk); in the typical case this will be about Ra/3.
The optimum load, Zopt, set by requiring equal currents from each valve, is approximately
(mu Rk2 - Ra2)/2 -- note that this is often quite small (could even be negative!) unless a large value for Rk2 (upper cathode resistor) is used. This is best done using a mu follower, which is a closely related circuit with different bias arrangements.
Assuming bypassed lower cathode, Rk2=750, Ra=4400, mu=35 I get
Zout = 633 (full formula) or 541 (simple formula)
Zopt = 10925
Bear in mind that you need to use the actual Ra and mu at the chosen bias point, not the quoted values for the valve in general. My guess is that 750 ohms at the cathode will bias the valve back, so Ra will be larger and mu smaller, but I am not familiar with the valve. Check the data sheet.
==============================================
Merlin Blencowe 的论述:
SRPP_Blencowe[1].zip
(231.27 KB, 下载次数: 220)
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