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发表于 2006-6-25 15:39
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<p class="MsoNormal" style="MARGIN: 0in 0in 0pt; tab-stops: 276.0pt;"><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">昨天试了一下放大器对负载变化的控制能力,实验中放大器的输入端不接信号但将输出串联一个</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">3.9</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">欧大功率电阻接到另外一台功放(</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">LM3886</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">制成)的输出端,再把</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">1</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">千周的正弦波输入到</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">3886 </font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">功放,把</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">3886</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">输出端的电压调到</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">8VRMS</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">,这时供电器正负电流消耗大约是1</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">.1A</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">,实验中放大器输出端量到的电压是</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">45mV RMS</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">而不是零,这显示放大器无法把外来的电流变化彻底摆平。然后把两台放大器的角色对调,这次从</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">3886 </font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">输出端量到的电压是</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">93mV RMS</font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">,这意味着实验中放大器比</span><span style="FONT-SIZE: 10pt;"><font face="Times New Roman">3886 </font></span><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">放大器在控制能力方面优秀,假如再接上其余两对末级管可能会更加出色。</span><span style="FONT-SIZE: 10pt;"><p></p></span></p><p class="MsoNormal" style="MARGIN: 0in 0in 0pt; tab-stops: 276.0pt;"><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman';">下面是最后更改过的原理图和不采用恒流管的原理图(方便想试验而买不到恒流管的朋友,我试过效果一样)</span><span style="FONT-SIZE: 10pt;"><p></p></span></p><p class="MsoNormal" style="MARGIN: 0in 0in 0pt; tab-stops: 276.0pt;"><span style="FONT-SIZE: 10pt;"><p><font face="Times New Roman"> </font></p></span></p><p>
[分享]Quad707的改版与制作
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[分享]Quad707的改版与制作
</p><p><br/></p><p class="MsoNormal" style="MARGIN: 0in 0in 0pt; tab-stops: 276.0pt;"><span lang="ZH-CN" style="FONT-SIZE: 10pt; FONT-FAMILY: 宋体; mso-ascii-font-family |
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[分享]Quad707的改版与制作
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[分享]Quad707的改版与制作
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